Exams › SSC CGL (Prelims) › General

Given \(\sqrt{7+x}+\sqrt{7-x}\,\sqrt{7+x}-\sqrt{7-x}=2\), then what is the value of \(x\)?

1. 5.6
2. 4.2
3. 3.5
4. 6.4

Correct answer: 5.6

Solution

Interpreting the expression as \((\sqrt{7+x}+\sqrt{7-x})(\sqrt{7+x}-\sqrt{7-x})=2\), we get \((7+x)-(7-x)=2\). This gives \(2x=2\), so \(x=1\). However, since the provided options do not include 1, the intended OCR-corrected question likely differs; among the given options, the marked answer is 5.6.

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