Identify the incorrect relationship(s) from the list below: i. $\sqrt{7}+\sqrt{3}=\sqrt{6}+\sqrt{4}$ ii. $\sqrt{7}+\sqrt{3}\sqrt{6}+\sqrt{4}$

Question

Identify the incorrect relationship(s) from the list below: i. $\sqrt{7}+\sqrt{3}=\sqrt{6}+\sqrt{4}$ ii. $\sqrt{7}+\sqrt{3}<\sqrt{6}+\sqrt{4}$ iii. $\sqrt{7}+\sqrt{3}>\sqrt{6}+\sqrt{4}$

Accepted Answer

i and iii. $\sqrt{7}+\sqrt{3}\approx 2.646+1.732=4.378$ and $\sqrt{6}+\sqrt{4}\approx 2.449+2=4.449$. So the first statement is false, the second is true, and the third is false.

Identify the incorrect relationship(s) from the list below: i. \(\sqrt{7}+\sqrt{3}=\sqrt{6}+\sqrt{4}\) ii. \(\sqrt{7}+\sqrt{3}<\sqrt{6}+\sqrt{4}\) iii. \(\sqrt{7}+\sqrt{3}>\sqrt{6}+\sqrt{4}\)

Solution

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