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Train A leaves Station X at 5:00 AM at 50 km/h. Train B leaves Station Y at 7:30 AM at 80 km/h. Both trains move towards each other. The distance between the stations is 500 km. When do they meet?

1. 10:30 AM
2. 11:00 AM
3. 10:23 AM
4. 12:00 PM

Correct answer: 10:23 AM

Solution

Train A travels from 5:00 AM to 7:30 AM for 2.5 hours, covering 125 km. Remaining distance is 375 km, and the relative speed is 50 + 80 = 130 km/h, so time taken after 7:30 AM is 375/130 ≈ 2.88 hours, i.e. about 2 hours 52 minutes. Thus they meet at about 10:23 AM.

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