If $a=0.01$, $b=0.02$, $c=-0.03$ and $a+b+c=0$, find $(a^3+b^3+c^3)\div(3abc)$.

Question

Accepted Answer

1. For three numbers with sum zero, $a^3+b^3+c^3=3abc$. Substituting this into the given expression gives $(3abc)/(3abc)=1$.

Solution