Exams › SSC CGL (Prelims) › General
Correct answer: 240 cm²
The lateral surface area of a square pyramid is given by \(\frac{1}{2} \times \text{perimeter of base} \times \text{slant height}\). Here, perimeter of the square base = \(4 \times 12 = 48\) cm. So, LSA = \(\frac{1}{2} \times 48 \times 10 = 240\) cm².