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What is the area of a sector of a circle with radius 9 cm and central angle 80°?
- 18π cm²
- 27π cm²
- 36π/5 cm²
- 72π/5 cm²
Correct answer: 18π cm²
Solution
The area of a sector is \(\frac{\theta}{360^\circ}\pi r^2\). Substituting \(\theta=80^\circ\) and \(r=9\) gives \(\frac{80}{360}\pi\times81=18\pi\) cm².
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