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The area of a sector of a circle of radius 6 cm with central angle \(120^\circ\) is:
- 12 π cm²
- 18 π cm²
- 24 π cm²
- 30 π cm²
Correct answer: 12 π cm²
Solution
The area of the full circle is \(\pi r^2=36\pi\). A \(120^\circ\) sector is one-third of the circle, so its area is \(\frac{120}{360}\times36\pi=12\pi\,\text{cm}^2\).
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