Exams › SSC CGL (Prelims) › General
If the base perimeter is 48 cm and the slant height is 12 cm, what is the lateral surface area of a square pyramid?
- 288 cm²
- 192 cm²
- 240 cm²
- 320 cm²
Correct answer: 288 cm²
Solution
The lateral surface area of a pyramid is given by \(\frac{1}{2} \times\) perimeter of base \(\times\) slant height. Substituting the values gives \(\frac{1}{2} \times 48 \times 12 = 288\) cm².
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