Exams › SSC CGL (Prelims) › General

Given that $m + \frac{1}{m} = 6$, find the value of $m^4 + \frac{1}{m^4}$.

1. 1154
2. 1186
3. 1194
4. 1218

Correct answer: 1154

Solution

From $m+\frac{1}{m}=6$, we get $m^2+\frac{1}{m^2}=6^2-2=34$. Then $m^4+\frac{1}{m^4}=(m^2+\frac{1}{m^2})^2-2=34^2-2=1154$.

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