Exams › SSC CGL (Prelims) › General

Given \(b=\sqrt{7}\), what is \((b+2)^2 + (b-2)^2\)?

1. 18
2. 20
3. 22
4. 24

Correct answer: 22

Solution

Expanding gives \((b+2)^2+(b-2)^2 = (b^2+4b+4)+(b^2-4b+4)=2b^2+8\). With \(b^2=7\), the value is \(2\cdot 7+8=22\).

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