Exams › SSC CGL (Prelims) › General
Correct answer: 26.56%
The park radius is 4 m and the outer radius is 4.5 m. Increase in area = \(\pi(4.5^2-4^2)=\pi(20.25-16)=4.25\pi\). Percentage increase = \(\frac{4.25\pi}{16\pi}\times100=26.5625\%\), approximately 26.56%.