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ExamsSSC CGL (Prelims)General

A circular park with diameter 8 m is surrounded by a 0.5 m wide path. What is the percentage increase in area?

  1. 40%
  2. 26.66%
  3. 26.56%
  4. 65%

Correct answer: 26.56%

Solution

The park radius is 4 m and the outer radius is 4.5 m. Increase in area = \(\pi(4.5^2-4^2)=\pi(20.25-16)=4.25\pi\). Percentage increase = \(\frac{4.25\pi}{16\pi}\times100=26.5625\%\), approximately 26.56%.

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