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ExamsSSC CGL (Prelims)General

In the number 87659_21, what is the smallest single digit that can replace the blank to make the entire number divisible by 11?

  1. 7
  2. 1
  3. 3
  4. 2

Correct answer: 1

Solution

For 87659d21, odd-position digits are 8, 6, 9, 2 (sum = 25) and even-position digits are 7, 5, d, 1 (sum = 13+d). The difference 25-(13+d) = 12-d must equal 0 or 11. Setting 12-d = 11 gives d = 1, which is a valid single digit.

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