Exams › SSC CGL (Prelims) › General
Correct answer: 1
For 87659d21, odd-position digits are 8, 6, 9, 2 (sum = 25) and even-position digits are 7, 5, d, 1 (sum = 13+d). The difference 25-(13+d) = 12-d must equal 0 or 11. Setting 12-d = 11 gives d = 1, which is a valid single digit.