Exams › SSC CGL (Prelims) › General
Correct answer: 208
Let the numbers be 4k, 5k, and 7k. Sum of squares: (4k)^2 + (5k)^2 + (7k)^2 = 16k^2 + 25k^2 + 49k^2 = 90k^2 = 15210. So k^2 = 169, k = 13. Sum = 4(13) + 5(13) + 7(13) = (4+5+7) x 13 = 16 x 13 = 208.