Exams › SSC CGL (Prelims) › General

If 4(z + 7)(2z - 1) = Az^2 + Bz + C, find the value of A + B + C.

1. 28
2. 32
3. 74
4. 81

Correct answer: 32

Solution

Expanding 4(z+7)(2z-1): first, (z+7)(2z-1) = 2z^2 - z + 14z - 7 = 2z^2 + 13z - 7. Multiplying by 4 gives 8z^2 + 52z - 28. Thus A=8, B=52, C=-28, and A+B+C = 32.

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