Exams › SSC CGL (Prelims) › General

In triangle PQR, the bisector of angle QPR meets side QR at point S. If PQ = 10 cm and PR = 14 cm, what is the ratio PS : SR? (Note: the question asks for BD:DC in original terms)

1. 5 : 3
2. 7 : 5
3. 5 : 2
4. 5 : 7

Correct answer: 5 : 7

Solution

By the Angle Bisector Theorem, the bisector of angle BAC divides BC in the ratio BD:DC = AB:AC = 10:14 = 5:7. The question asks for BD:DC (the two segments of BC), which equals 5:7.

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