Exams › SSC CGL (Prelims) › General
In right-angled triangle PQR, angle P = 90 degrees and PD is perpendicular to QR. If the area of triangle PQR is 80 cm^2 and QR = 16 cm, find the length of PD.
- 10 cm
- 24 cm
- 18 cm
- 12 cm
Correct answer: 10 cm
Solution
The area of triangle PQR can be expressed as (1/2) * QR * PD, where QR is the base and PD is the perpendicular height from P to QR. Substituting: 80 = (1/2) * 16 * PD, giving PD = 80/8 = 10 cm.
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