Exams › SSC CGL (Prelims) › General

A number r, when divided by 8, leaves a remainder of 3. What is the remainder when (r^2 + 6r + 7) is divided by 8?

1. 4
2. 3
3. 1
4. 2

Correct answer: 2

Solution

Since r ≡ 3 (mod 8), compute r^2 ≡ 9 ≡ 1, 6r ≡ 18 ≡ 2, and the constant 7 (mod 8). Sum: 1 + 2 + 7 = 10 ≡ 2 (mod 8). The remainder is 2.

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