Exams › SSC CGL (Prelims) › General

Given that 4x^2 + y^2 = 40 and xy = 6, find the value of (2x + y).

1. 6
2. 8
3. 5
4. 4

Correct answer: 8

Solution

(2x + y)^2 = 4x^2 + 4xy + y^2 = 40 + 4 x 6 = 40 + 24 = 64. Taking the positive square root gives 2x + y = 8. Option B is correct.

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