Exams › SSC CGL (Prelims) › General
A regular hexagonal mirror has a side of 18 cm. If 12% of its area is hidden by the frame, what is the visible glass area?
- 690.2 cm^2
- 710.5 cm^2
- 740.7 cm^2
- 758.6 cm^2
Correct answer: 740.7 cm^2
Solution
The hexagon's area is (3*sqrt(3)/2)*18^2 approx 841.8 cm^2, and 88% of it remains visible, giving about 740.7 cm^2. Thus 740.7 cm^2 is correct.
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