Exams › SSC CGL (Prelims) › General

A regular hexagon has a perimeter of 48 cm. Using sqrt(3) = 1.732, what is its area to the nearest hundredth?

1. 156.25 cm^2
2. 166.27 cm^2
3. 186.35 cm^2
4. 176.40 cm^2

Correct answer: 166.27 cm^2

Solution

Side = 48/6 = 8 cm. Area = (3*sqrt(3)/2)*8^2 = (3*1.732/2)*64 = 2.598*64 = 166.27 cm^2.

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