StreakPeaked· Practice

ExamsSSC CGL (Prelims)General

If cos B = p/q where B lies in the interval (0, pi/2), express sin B in terms of p and q.

  1. sqrt(q^2 - p^2) / q
  2. sqrt(q^2 + p^2) / p
  3. sqrt(q^2 - p^2) / p
  4. p / sqrt(q^2 - p^2)

Correct answer: sqrt(q^2 - p^2) / q

Solution

From sin^2 B = 1 - cos^2 B = 1 - (p/q)^2 = (q^2 - p^2)/q^2, taking the positive root (first quadrant) gives sin B = sqrt(q^2 - p^2)/q.

Related SSC CGL (Prelims) General questions

⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →