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A solid cylinder of radius 6 cm and height 14 cm has a coaxial cylindrical hole of radius 2 cm drilled straight through its full length. Taking pi = 22/7, what is the volume of the solid that remains?

1. 1500 cm^3
2. 1408 cm^3
3. 1300 cm^3
4. 1208 cm^3

Correct answer: 1408 cm^3

Solution

The leftover solid is the outer cylinder minus the cylindrical hole. Using pi*h*(R^2 - r^2) = (22/7)*14*(36 - 4) = 22*2*32 = 1408 cm^3.

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