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A hollow spherical shell has an inner radius of 3 cm and an outer radius of 6 cm. Find the approximate volume of the metal forming the shell.
- 840.22 cm^3
- 791.68 cm^3
- 905.14 cm^3
- 700.50 cm^3
Correct answer: 791.68 cm^3
Solution
The metal volume equals the difference of the two spherical volumes: (4/3) x pi x (6^3 - 3^3) = (4/3) x pi x 189, which is about 791.68 cm^3.
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