Exams › SSC CGL (Prelims) › General

A circle of radius 12 cm contains a sector subtending a central angle of 90 degrees. Taking pi = 3.14, what is the area of the minor segment cut off by the chord of this sector?

1. 41.04 cm^2
2. 36.52 cm^2
3. 45.18 cm^2
4. 39.24 cm^2

Correct answer: 41.04 cm^2

Solution

The 90-degree sector area is (1/4)(3.14)(144) = 113.04 cm^2, and the isosceles right triangle of legs 12 has area 72 cm^2. The minor segment is 113.04 - 72 = 41.04 cm^2.

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