Exams › SSC CGL (Prelims) › General
Correct answer: n^2 / (n^2 - m^2)
Using 1 + cot^2 A = cosec^2 A = 1/sin^2 A, and sin^2 A = 1 - m^2/n^2 = (n^2 - m^2)/n^2, the value is n^2/(n^2 - m^2).
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