Exams › SSC CGL (Prelims) › General › Compound Interest
9 questions with worked solutions.
Q1. Find the compound interest on ₹12,000 at 8% per annum for 2 years 6 months, compounded annually.
Answer: ₹ 2,556.67
For annual compounding, first calculate amount after 2 years: \(12000\times1.08^2=13996.8\). For the remaining 6 months, add simple interest at 8% for half a year on this amount: \(13996.8\times0.04=559.872\). Thus total CI \(=13996.8+559.872-12000=2556.672\approx ₹2556.67\).
Answer: ₹ 3,840
If the amount after 2 years at 15% compound interest is ₹4235, then \(P(1.15)^2=4235\). So \(P=4235/1.3225=3200\). Therefore, 120% of the principal is \(1.2\times3200=3840\).
Answer: 7.5%
For annual compounding, \(A=P(1+r/100)^2\). Here \(\frac{9245}{8000}=1.155625\), so \((1+r/100)^2=1.155625\). Taking square root gives \(1+r/100=1.075\), hence \(r=7.5\%\).
Answer: 32
If the amount triples in 8 years, then after 8 years the factor is 3. To become 81 times, we need 81 = 3^4, so it takes 4 such periods. Therefore, the total time is 4 × 8 = 32 years.
Answer: 15 years
If the money becomes 3 times in 5 years, then every 5 years it is multiplied by 3. To become 27 times, we need $27=3^3$, i.e., three such periods. Hence, time required is $3\times 5=15$ years.
Answer: Rs. 10,285
For compound interest, the interest in a particular year is calculated on the amount accumulated up to the previous year. After 2 years, the amount is 85,000 × 1.1² = 102,850, so the 3rd-year interest is 10% of this, i.e. 10,285.
Answer: 25%
With annual compounding, the amount in year 3 is the year 2 amount multiplied by $1+r$. So $2000/1600 = 1.25$, giving $r = 0.25 = 25\%$.
Answer: ₹ 9,680
For compound interest, \(A = P(1 + r/100)^n\). Here \(P=8000\), \(r=10\), and \(n=2\), so \(A = 8000 \times 1.1^2 = 8000 \times 1.21 = 9680\).
Answer: 33.33%
For 1 year, the compound interest formula becomes $A=P\left(1+\frac{R}{100}\right)$. Here, interest = 600 - 450 = 150. So $150 = 450\cdot \frac{R}{100}$, giving $R = 33.33\%$.