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A circuit contains an ammeter, a battery of 30V and a resistance 40.8Ω all connected in series. If the ammeter has a coil of resistance 480Ω and a shunt of 20Ω, the reading in the ammeter will be:
- 0.25 A
- 2 A
- 1 A
- 0.5 A
Correct answer: 0.5 A
Solution
The total resistance of the circuit is calculated by combining the resistance of the shunt and the ammeter coil in parallel, then adding the series resistance. Using Ohm's law, the current is determined as 0.5 A.
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