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For a metallic wire, the ratio \( \frac{V}{i} \) (where, \( \mathbf{V}= \) applied potential difference and \( \mathbf{i}= \) current flowing

1. is independent of temperature
2. increases as the temperature rises
3. decreases as the temperature rises
4. increases or decreases as temperature rises depending upon the metal.

Correct answer: increases as the temperature rises

Solution

For a metallic wire, \(V/i\) is the resistance. In metals, increasing temperature increases lattice vibrations, which makes electron flow harder, so resistance rises. Therefore \(V/i\) increases as temperature rises.

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