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This is a balanced Wheatstone bridge condition, 5/R = l₁/100 = l₂/100.

1. R = 15 Ω
2. R = 10 Ω
3. R = 20 Ω
4. R = 25 Ω

Correct answer: R = 10 Ω

Solution

In a balanced Wheatstone bridge, the ratio of resistances in one branch equals the ratio in the other. From the given condition, 5/R = l₁/100 = l₂/100, we can simplify to find R = 10 Ω.

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