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In series grouping equivalent resistance R_series = nR. In parallel grouping equivalent resistance R_parallel = R / n. Using the relation I = E / (nR + R), solve for n when 10I = E / (n + R).

1. n = 10
2. n = 5
3. n = 15
4. n = 20

Correct answer: n = 5

Solution

From the given equation, substitute R_series = nR into I = E / (nR + R). Simplify to get I = E / R(n + 1). Using 10I = E / (n + R), equate and solve for n, yielding n = 5.

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