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The resistances in the two arms of the meter bridge are 5Ω and RΩ, respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6 l₁. The resistance ‘R’ is:

1. 10Ω
2. 15Ω
3. 20Ω
4. 25Ω

Correct answer: 20Ω

Solution

When R is shunted with an equal resistance, the effective resistance becomes R/2. Using the meter bridge principle and the given balance point shift, we can set up the ratio of resistances and solve for R. The calculation yields R = 20Ω.

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