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If nearly 10⁵ coulombs liberate 1 gm-equivalent of aluminium, then the amount of aluminium (equivalent weight 9), deposited through electrolysis in 20 minutes by a current of 50 amp will be

1. 0.6 gm
2. 0.09 gm
3. 5.4 gm
4. 10.8 gm

Correct answer: 0.6 gm

Solution

The charge passed in 20 minutes is Q = I × t = 50 × 20 × 60 = 60000 C. Using the relation, mass deposited = (equivalent weight × charge passed) / (96500), we get mass = (9 × 60000) / 96500 = 0.6 gm.

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