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A car battery has e.m.f. 12 volt and internal resistance 5 × 10⁻² ohm. If it draws 60 amp current, the terminal voltage of the battery will be
- 15 volt
- 3 volt
- 5 volt
- 9 volt
Correct answer: 9 volt
Solution
The terminal voltage of a battery is given by V = E - Ir, where E is the e.m.f., I is the current, and r is the internal resistance. Substituting the values: V = 12 - (60 × 0.05) = 12 - 3 = 9 volts.
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