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ExamsNEETPhysics

A steady current of 1.5 amp flows through a copper voltameter for 10 minutes. If the electrochemical equivalent of copper is 30×10⁻⁵ g coulomb⁻¹, the mass of copper deposited on the electrode will be

  1. 0.50 g
  2. 0.67 g
  3. 0.27 g
  4. 0.40 g

Correct answer: 0.67 g

Solution

The mass of copper deposited is given by m = ZIt, where Z is the electrochemical equivalent, I is the current, and t is the time in seconds. Here, Z = 30×10⁻⁵ g/C, I = 1.5 A, and t = 10×60 = 600 s. Substituting, m = (30×10⁻⁵)(1.5)(600) = 0.67 g.

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