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Current through 3 Ω resistor is 0.8 amp., then potential drop through 4 Ω resistor is

1. 9.6 V
2. 2.6 V
3. 4.8 V
4. 1.2 V

Correct answer: 4.8 V

Solution

Using Ohm's Law (V = IR), the potential drop across the 4 Ω resistor is calculated as V = 0.8 A × 4 Ω = 4.8 V.

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