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A charged particle having drift velocity of 7.5 × 10⁻⁴ m s⁻¹ in an electric field of 3 × 10⁻¹⁰ V m⁻¹, has a mobility in m² V⁻¹ s⁻¹ of:
- 2.5 × 10⁶
- 2.5 × 10⁻⁶
- 2.25 × 10⁻¹⁵
- 2.25 × 10¹⁵
Correct answer: 2.5 × 10⁻⁶
Solution
Mobility (μ) is defined as the drift velocity (v_d) per unit electric field (E). Using the formula μ = v_d / E, we substitute v_d = 7.5 × 10⁻⁴ m/s and E = 3 × 10⁻¹⁰ V/m. This gives μ = (7.5 × 10⁻⁴) / (3 × 10⁻¹⁰) = 2.5 × 10⁶ m²/V·s.
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