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If C = 10 μF, d = 8 cm, and d is halved, then the new capacitance is:

1. C' = 20 μF
2. C' = 5 μF
3. C' = 10 μF
4. C' = 15 μF

Correct answer: C' = 20 μF

Solution

The capacitance of a parallel plate capacitor is inversely proportional to the distance between the plates (C ∝ 1/d). Halving the distance doubles the capacitance, so the new capacitance is 20 μF.

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