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When a proton is accelerated through \( 1 \, \text{V} \), then its kinetic energy will be
- 1840 eV
- 13.6 eV
- 1 eV
- 0.54 eV
Correct answer: 1 eV
Solution
When a proton is accelerated through a potential difference of 1 V, it gains an energy equal to the charge of the proton (1 elementary charge) multiplied by the potential difference. This equals 1 eV, as 1 eV is defined as the energy gained by a charge of 1e when accelerated through 1 V.
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