Exams › NEET › Physics

A parallel plate condenser with oil between the plates (dielectric constant of oil K = 2) has a capacitance C. If the oil is removed, then capacitance of the capacitor becomes

1. √2 C
2. 2C
3. C/√2
4. C/2

Correct answer: C/2

Solution

The capacitance of a parallel plate capacitor with a dielectric is given by C = Kε₀A/d. When the dielectric is removed (K = 1), the capacitance becomes C' = ε₀A/d. Thus, C' = C/K = C/2.

Related NEET Physics questions

• A positively charged rod is brought near an uncharged conductor. If the rod is then suddenly withdrawn, the charge left on the conductor will be :
• Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?
• In a region, the potential is represented by V(x, y, z) = 6x − 8xy − 8y + 6yz, where V is in volts and x, y, z are in meters. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is:
• If potential (in volts) in a region is expressed as V(x, y, z) = 6xy − y + 2yz, the electric field (in N/C) at point (1, 1, 0) is:
• What is the electrostatic force between the metal plates of a capacitor?
• When a proton is accelerated through \( 1 \, \text{V} \), then its kinetic energy will be

⚔️ Practice NEET Physics free + battle 1v1 →