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A 4 μF conductor is charged to 400 volts and then its plates are joined through a resistance of 1 kΩ. The heat produced in the resistance is

1. 0.16 J
2. 1.28 J
3. 0.64 J
4. 0.32 J

Correct answer: 0.64 J

Solution

The heat produced in the resistance equals the initial energy stored in the capacitor, which is given by U = (1/2)CV². Substituting C = 4 μF = 4 × 10⁻⁶ F and V = 400 V, we get U = (1/2)(4 × 10⁻⁶)(400)² = 0.32 J. Hence, the heat produced is 0.32 J.

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