Exams › NEET › Physics
The four capacitors, each of 25 μF are connected as shown in fig. The dc voltmeter reads 200 V. The charge on each plate of capacitor is
- 2 × 10⁻³ C
- 5 × 10⁻³ C
- 2 × 10⁻² C
- 5 × 10⁻² C
Correct answer: 2 × 10⁻³ C
Solution
The capacitors are connected in a combination of series and parallel. The equivalent capacitance is calculated, and the total charge is found using Q = CV. For each capacitor in series, the charge remains the same. Using the given values, the charge on each plate is 2 × 10⁻³ C.
Related NEET Physics questions
- A positively charged rod is brought near an uncharged conductor. If the rod is then suddenly withdrawn, the charge left on the conductor will be :
- Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?
- In a region, the potential is represented by V(x, y, z) = 6x − 8xy − 8y + 6yz, where V is in volts and x, y, z are in meters. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is:
- If potential (in volts) in a region is expressed as V(x, y, z) = 6xy − y + 2yz, the electric field (in N/C) at point (1, 1, 0) is:
- What is the electrostatic force between the metal plates of a capacitor?
- When a proton is accelerated through \( 1 \, \text{V} \), then its kinetic energy will be
⚔️ Practice NEET Physics free + battle 1v1 →