StreakPeaked· Practice

ExamsNEETPhysics

Three capacitors each of capacity 4 μF are to be connected in such a way that the effective capacitance is 6 μF. This can be done by

  1. connecting two in parallel and one in series
  2. connecting all of them in series
  3. connecting them in parallel
  4. connecting two in series and one in parallel

Correct answer: connecting two in parallel and one in series

Solution

To achieve an effective capacitance of 6 μF, two capacitors (4 μF each) are connected in parallel, giving an equivalent capacitance of 8 μF. This combination is then connected in series with the third capacitor (4 μF), resulting in an effective capacitance of 6 μF.

Related NEET Physics questions

⚔️ Practice NEET Physics free + battle 1v1 →