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A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates:

1. does not change
2. becomes zero
3. increases
4. decreases

Correct answer: increases

Solution

When the battery is disconnected, the charge on the capacitor remains constant. Increasing the distance between the plates reduces the capacitance, and since V = Q/C, the potential difference increases.

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