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A bullet of mass 2 g is having a charge of 2 μC. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of 10 m/s?
- 50V
- 5kV
- 50kV
- 5V
Correct answer: 50V
Solution
The kinetic energy gained by the bullet is equal to the work done by the electric field, which is given by qV. Using the equation for kinetic energy, (1/2)mv^2 = qV, we substitute m = 2 × 10^-3 kg, v = 10 m/s, and q = 2 × 10^-6 C. Solving, V = (1/2)(2 × 10^-3)(10^2) / (2 × 10^-6) = 50 V.
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