Exams › NEET › Physics
The potential energy of a particle in a force field is U = A / r² - B / r, where A and B are positive constants and r is the distance of the particle from the centre of the field. For stable equilibrium, the distance of the particle is:
- A / 2B
- 24 / B
- A / B
- B / 4
Correct answer: A / 2B
Solution
For stable equilibrium, the force acting on the particle must be zero, which is derived from the condition dU/dr = 0. Differentiating U = A/r² - B/r with respect to r and solving for r gives r = A / 2B.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →