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A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂. Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁ > m₂ then:

1. E₁ = E₂
2. E₁ < E₂
3. E₁ = m₁/m₂
4. E₁ > E₂

Correct answer: E₁ < E₂

Solution

Since both particles have the same momentum (p = m*v), the velocity of the lighter particle (m₂) will be greater than that of the heavier particle (m₁). Kinetic energy is proportional to the square of velocity (KE = p²/2m). Therefore, the lighter particle (m₂) will have a higher kinetic energy (E₂ > E₁).

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