Exams › NEET › Physics

Three concentric spherical shells have radii a, b and c (a < b < c) and have surface charge densities σ, –σ and σ respectively. If Vₐ, Vᵦ and V꜀ denote the potentials of the three shells, then for c = a + b, we have

1. V꜀ = Vᵦ ≠ Vₐ
2. V꜀ ≠ Vᵦ ≠ Vₐ
3. V꜀ = Vᵦ = Vₐ
4. V꜀ ≠ Vₐ ≠ Vᵦ

Correct answer: V꜀ = Vᵦ = Vₐ

Solution

The potential at any point inside a spherical shell is constant and equal to the potential on its surface. Since the shells are concentric and the outermost shell's radius is the sum of the inner two (c = a + b), the potentials of all three shells will be equal due to symmetry and charge distribution.

Related NEET Physics questions

• A positively charged rod is brought near an uncharged conductor. If the rod is then suddenly withdrawn, the charge left on the conductor will be :
• Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?
• In a region, the potential is represented by V(x, y, z) = 6x − 8xy − 8y + 6yz, where V is in volts and x, y, z are in meters. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is:
• If potential (in volts) in a region is expressed as V(x, y, z) = 6xy − y + 2yz, the electric field (in N/C) at point (1, 1, 0) is:
• What is the electrostatic force between the metal plates of a capacitor?
• When a proton is accelerated through \( 1 \, \text{V} \), then its kinetic energy will be

⚔️ Practice NEET Physics free + battle 1v1 →