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At surface of earth, time taken in falling h distance.

1. t = √(2h/g)
2. t = √(h/2g)
3. t = √(h/g)
4. t = √(2g/h)

Correct answer: t = √(2h/g)

Solution

The time taken to fall a distance h under gravity is derived from the equation of motion: h = (1/2)gt². Solving for t gives t = √(2h/g).

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