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A body is accelerated by applying a force of 30 N. The change in the momentum of the body after 2 sec is?

1. \( 7.5 \mathrm{kg}-\mathrm{m} / \mathrm{s} \)
2. \( 30 \mathrm{kg}-\mathrm{m} / \mathrm{s} \)
3. \( 120 \mathrm{kg}-\mathrm{m} / \mathrm{s} \)
4. \( 60 \mathrm{kg}-\mathrm{m} / \mathrm{s} \)

Correct answer: \( 60 \mathrm{kg}-\mathrm{m} / \mathrm{s} \)

Solution

For a constant force, the impulse equals the change in momentum: \(\Delta p = F\Delta t\). Here, \(30\,\text{N} \times 2\,\text{s} = 60\,\text{N·s}\), and \(1\,\text{N·s} = 1\,\text{kg·m/s}\).

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