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A beaker full of hot water is kept in a room. If it cools from 80°C to 75°C in t₁ minutes, from 75°C to 70°C in t₂ minutes and from 70°C to 65°C in t₃ minutes, then

1. t₁ = t₂ = t₃
2. t₁ < t₂ = t₃
3. t₁ < t₂ < t₃
4. t₁ > t₂ > t₃

Correct answer: t₁ < t₂ < t₃

Solution

According to Newton's Law of Cooling, the rate of cooling is proportional to the temperature difference between the object and its surroundings. As the temperature difference decreases, the cooling rate slows down, making t₃ > t₂ > t₁.

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